﻿ If f (x) = |x – 2| and g(x) = f (f (x)), then for x > 20, g’(x) is equal to : Kaysons Education

# If f (x) = |x – 2| And g(x) = f (f (x)), Then For x > 20, g’(x) Is Equal To

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## Question

### Solution

Correct option is

1

Since (x) = |x – 2| = x – 2 for x > 2, we have g(x) = ((x))

= f (x – 2) = x – 4 for x > 4. Hence g’(x) = 1 for x > 20.

#### SIMILAR QUESTIONS

Q1

Suppose that f(x) = [x], the least integer function then

Q2

is equal to

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for real and y. If f’(0) exists and equals – 1 and (0) = 1 then the value of f(2) is

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If f : R  R is a function such that (x) = x3 + x2 f’(1) + xf’’(2) + f’’’(3) for x Ïµ R then the value of f (2) is

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and n are integers, m ≠ 0, n > 0, and let p be the left hand derivative of |x – 1| at x = 1. If

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