If The Function f (x) = | x2 + a | x | +b| Has Exactly Three Points Of Non-differentiability, Then Which Of The Following Can Be True?

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Question

If the function f (x) = | x2 + a | x | +b| has exactly three points of non-differentiability, then which of the following can be true?

Solution

Correct option is

b = 0, a < 0

 has three points of non-differentiability.

∴  f (x) is non differentiable at x = 0, x1x2  

⇒ x2 + ax + b = 0 has one root zero and other positive root. 

 b = 0 and a < 0, is one of the case.

 

 

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