﻿ If the function f (x) = | x2 + a | x | +b| has exactly three points of non-differentiability, then which of the following can be true? : Kaysons Education

# If The Function f (x) = | x2 + a | x | +b| Has Exactly Three Points Of Non-differentiability, Then Which Of The Following Can Be True?

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## Question

### Solution

Correct option is

b = 0, a < 0

has three points of non-differentiability.

∴  f (x) is non differentiable at x = 0, x1x2

⇒ x2 + ax + b = 0 has one root zero and other positive root.

b = 0 and a < 0, is one of the case.

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