﻿ What is the distance of closest approach when a 5.0 MeV proton approaches a gold nucleus (Z = 79)? Given,       . : Kaysons Education

# What Is The Distance Of Closest Approach When A 5.0 MeV Proton Approaches A Gold Nucleus (Z = 79)? Given,       .

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## Question

### Solution

Correct option is

The (positive) charge on the proton is e (half of that on -particle) Therefore, the electrostatic potential energy at the distance of closest approach r0 is . Thus, as above

Putting the given values :

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