In A Head-on Collision Between An -particle And Gold (Z = 79) Nucleus, The Closest Distance Of Approach Is 41.3 Fermi. Calculate The Energy Of The -particle. (1 Fermi = 10–15 m) 

Potential energy of list electron is

The ratio of ionization energy of hydrogen atom in terms of Reedley constant  is given

An -part ale of energy 5Mev is scattered through 180 by a fined uranium nucleus. The distance of the closed approach is of the order of:

An -particle with kinetic energy 10 MeV is heading towards a stationary point-nucleus of atomic number Z = 50. Calculate the distance of closest approach.

An -particle with kinetic energy 10 MeV is heading towards a stationary point-nucleus of atomic number Z = 50. Calculate the distance of closest approach.

What is the distance of closest approach when a 5.0 MeV proton approaches a gold nucleus (Z = 79)? Given, 

.

An -particle after passing through a potential difference of  falls on a silver foil. The atomic number of silver is 47. Calculate the kinetic energy of the -particle at the time of falling on the foil. 

A beam of -particles of velocity  is scattered by a gold (Z = 79) foil. Find out the distance closest approach of the -particle to the gold nucleus. The value of charge/mass for -particle is .

What is the upper limit of the radius of the gold nuclues (Z = 79), if an -particle of energy 12.5 MeV is deflected back by the nucleus through 180^o.

Write down the expression for the radii of orbits of hydrogen atom. Calculate the radius of the smallest orbit.