﻿ In a head-on collision between an -particle and gold (Z = 79) nucleus, the closest distance of approach is 41.3 fermi. Calculate the energy of the -particle. (1 fermi = 10–15 m)  : Kaysons Education

# In A Head-on Collision Between An -particle And Gold (Z = 79) Nucleus, The Closest Distance Of Approach Is 41.3 Fermi. Calculate The Energy Of The -particle. (1 Fermi = 10–15 m)

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## Question

### Solution

Correct option is

5.5 MeV

The distance of closest approach of an -partcle of energy K is

.

Putting the given known values, we get

.

= 5.5 MeV.

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