﻿ An electron of energy 20 eV collides with a hydrogen atom in the ground state. As a result, the atom is excited to a higher energy state and the electron is scattered with reduced velocity. The atom subsequently returns to its ground state with emission of radiation of wavelength . Find the velocity of the scattered electron.         : Kaysons Education

# An Electron Of Energy 20 EV Collides With A Hydrogen Atom In The Ground State. As A Result, The Atom Is Excited To A Higher Energy State And The Electron Is Scattered With Reduced Velocity. The Atom Subsequently Returns To Its Ground State With Emission Of Radiation Of wavelength . Find The Velocity Of The Scattered Electron.

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## Question

### Solution

Correct option is

The energy lost by the electron in exciting the hydrogen atom is equal to the energy of radiation of wavelength  m, that is,

The initial energy of the electron is

Therefore, the kinetic energy of the scattered electron is

.

If v be the velocity of the scattered electron, then .

.

#### SIMILAR QUESTIONS

Q1

In Bohr’s model of hydrogen atom, the radius of the first electron orbit is 0.53 Å. What will be the radius of the third orbit? What of the first orbit of singly-ionised helium atom?

Q2

Which energy state of the triply ionized beryllium (Be+++) has the same orbital radius as that of the ground state of hydrogen? Compare the energies of the two states.

Q3

Calculate the speed of an electron revolving in the first orbit around the nucleus of a hydrogen atom in order that in order that it may not be pulled into the nucleus by electrostatic attraction.

Q4

Determine the speed of electron in the n = 3 orbit of He+. Is the non-relativistic approximation valid? Datas as above.

Q5

The total energy (potential + kinetic) of an electron in the ground state of Bohr model of hydrogen atom is –13.6 eV. Obtain the values of the potential energy U and kinetic energy K in eV. Include –ve or +ve sign as required.

Q6

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Q7

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Q8

A hydrogen atom rises from its n = 1 state to the n = 4 state by absorbing energy. If the potential energy of the atom in n = 1 state be –13.6 eV, thencalculate : potential energy in n = 4 state.

Q9

The ionization energy of the hydrogen atom is given to be 13.6 eV. A photon falls on a hydrogen atom which is initially in the ground state and excites it to the n = 4 state.  Calculate the wavelength of the photon.

Q10

A proton captures a free electron whose kinetic energy is zero and forms a hydrogen atom of lowest energy-level (n = 1). If a photon is emitted in this process, what will be the wavelength of radiation? In which region of electromagnetic spectrum, will this radiation fall? (Ionisation potential of hydrogen atom = 13.6 V).