In The Bohr Model Of The Hydrogen Atom, The Ratio Of The Kinetic Energy To The Total Energy Of The Electron In A Quantum State n is

A hydrogen atom rises from its n = 1 state to the n = 4 state by absorbing energy. If the potential energy of the atom in n = 1 state be –13.6 eV, thencalculate : potential energy in n = 4 state. 

The ionization energy of the hydrogen atom is given to be 13.6 eV. A photon falls on a hydrogen atom which is initially in the ground state and excites it to the n = 4 state.  Calculate the wavelength of the photon. 

An electron of energy 20 eV collides with a hydrogen atom in the ground state. As a result, the atom is excited to a higher energy state and the electron is scattered with reduced velocity. The atom subsequently returns to its ground state with emission of radiation of wavelength . Find the velocity of the scattered electron.

A proton captures a free electron whose kinetic energy is zero and forms a hydrogen atom of lowest energy-level (n = 1). If a photon is emitted in this process, what will be the wavelength of radiation? In which region of electromagnetic spectrum, will this radiation fall? (Ionisation potential of hydrogen atom = 13.6 V, ).  

The de Broglie wavelength of a neutron at 927^oC is . What will be its wavelength at 27^oC?

What is the de Broglie wavelength of an electron of energy 1800 eV? Mass of electron  and Planck’s constant .

Moving with the same velocity, which of the following has the longest de Broglie wavelength? 

The de Broglie wavelength of an electron moving with a velocity  is equal to that a photon. The ratio of the kinetic energy of the electron to that of the photon is 

The distance of the closest approach of an alpha particle fired at a nuclear with momentum p is r₀. The distance of the closest approach when the alpha particle is fired at the same nucleus with momentum 2p will be   

The mass per nucleon in a heavy hydrogen atom is