## Question

### Solution

Correct option is

27.6 keV, 30 keV

The maximum energy of the X-ray photon is

= 27.6 keV.

For getting X-ray photons of 27.6 keV energy, the electrons striking the target in the X-ray tube must possess kinetic energy of at least 27.6 keV. Therefore, accelerating voltage of order of 30 keV is required in the tube for accelerating electrons.

#### SIMILAR QUESTIONS

Q1

The binding energy of the innermost electron in tungsten is 40 keV. To produce characteristics X-rays using a tungsten target in an X-ray tube, the accelerating voltage should be greater than

Q2

X-rays of wavelength  are incident normally on a crystal and the second order reflection on diffraction from the crystal observed at an angle of 45o. The lattice constant of the crystal is

Q3

The frequency of  line of a source of atomic number Z is proportional to

Q4

A direct X-ray photograph of the intestines is not generally taken by the radiologists because :

Q5

X-rays which can penetrate through longer distance in substances are called.

Q6

The target in an X-rays tube should be a:

Q7

The maximum frequency of the X-rays produced in an X-ray tube

Q8

Which one of the following parameters of the emitted X-rays increases when the potential difference between the electrodes of an X-ray tube is increased?

Q9

Calculate the energy of a photon, in electron-volt (eV) and in watt-hour (W h), of wavelength 6600 Å.

Q10

In an accelerator experiment on high-energy collisions of the electrons with positrons, a certain event is interpreted as the annihilation of an electron-positron pair of total energy 10.2 BeV into two -rays of equal energy. Find the wavelength associated with each -ray.