Question

Solution

Correct option is

2.0 V

If v be the frequency of light falling on the metal and v0 the threshold frequency, then by photoelectric equation, the maximum kinetic energy of the emitted photoelectrons is given by Also, if V0 be the cut-off voltage, then From these two equations, we have  = 2.0 V.

SIMILAR QUESTIONS

Q1

An isolated hydrogen atom emits a photon of energy 10.2 eV. Calculate momentum of the photon. Q2

Light of wavelength 3500 Å is incident on two metals A and B. Which metal will emit photoelectrons, if their work functions are 4.2 eV and 1.9 eV respectively? Q3

A light beam of wavelength 6000 Å and intensity falls normally on a photon-cathode of surface area 1 cm2 and work function 2 eV. Assuming that there is no loss of light by reflection etc., calculate the number of photoelectrons emitted per second. Q4

When a beam of 10.6-eV photons of intensity 2.0 Wm–2 falls on a platinum surface of area and work function 5.6 eV, 0.53% of the incident photons eject photoelectrons. Find the number of photoelectrons emitted per second and their minimum and maximum energies (in eV). Take .

Q5

The work function for cesium is 1.8 eV. Light of 5000 Å is incident on it. Calculate maximum velocity of the emitted electrons.

Q6

If photoelectrons are to be emitted from a potassium surface with a speedof , what frequency of radiation must be used? The threshold frequency for potassium is  Q7

A sheet of silver is illuminated by monochromatic ultraviolet radiation of wavelength 1810 Å. What is the maximum energy of the emitted electrons? The threshold wavelength for silver is 2640 Å. Q8

The work function for the surface of aluminium is 4.2 eV. How much potential difference will be required to stop the emission of maximum-energy electrons emitted by light of 2000 Å wavelength?

Q9

What will be the wavelength of that incident light for which the stopping potential will be zero? Q10

The work function of caesium is 2.14 eV. Find the threshold frequency for caesium. 