## Question

A sonometer wire is in unison with a tuning fork. Keeping the tension unchanged, the length of the wire between the bridge is doubled. The tuning fork can still be in resonance with the wire, provided the wire now vibrates in

### Solution

2 segments

We know that *vL* = constant. If the length *L* is doubled, the frequency becomes half. Since the frequency of the second harmonic is twice that of the first harmonic (fundamental), the string must vibrate in **2 **segments now.

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