For a common base transistor circuit, the emitter-current and the collector-current are 1 mA and 0.96 mA respectively. Calculate the current gain and base current.
0.96, 0.04 mA
By definition, the direct current gain is given by
The base-current is emitter-current – collector-current. Thus
= 0.04 mA.
The depletion layer in the p-n junction is formed by
When a forward bias is applied to a p-n junction, it :
The resistance of a forward-biased p-n junction is :
When a semiconductor device is connected with a battery and a resistance in series, a current flows in the circuit. The current almost vanishes if the polarity of the battery is reversed. The device may be :
The circuit contains two diodes, each with a forward resistance of and with infinite backward resistance. If the battery voltage is 6 V, the current through the resistance is
Two identical p-n junction may be connected in series with a battery in three ways. The potential drops across the two p-n junction are equal in :
In case of p-n junction diode at high reverse-bias, the current rises sharply. The value of reverse bias is known as :
A junction diode can be used for :
A p-n junction diode cannot be used :
The current gain for common-emitter amplifier is 59. If the emitter-current is 6.0 mA, find (i) base-current, and (ii) collector-current.