The current-gain of a transistor in a common-base arrangement is 0.98. Find the change in collector-current corresponding to a change of 5.0 mA in emitter-current. What would be the change in the base-current?
4.9 mA, 0.1 mA
By definition, the a-c current-gain in common-base arrangement of a transistor is give by
= 4.9 mA.
We know that the base-current is emitter-current minus collector-current, that is
= 0.1 mA.
The value of from factor of full wave rectifier is
When the p-end of the p-n junction is connected to the negative terminal of the battery and the n-end to the positive terminal of the battery, then thep-n junction behaves like :
n-type semiconductor is formed :
An n-type and a p-type silicon can be obtained by doping pure silicon with :
An n-type semiconductor is :
The drift current in a p-n junction is :
The diffusion current in a p-n junction is
In a p-n-p transistor with normal bias:
The base-current of a transistor is and the collector-current is 2.05 mA. A change of in the base-current produces a change of 0.65 mA in the collector current. Find .
In a common-base amplifier the load-resistance of the output circuit is and the resistance of the input circuit is . If current-gain be 0.95, calculate the voltage-gain and the power gain.