## Question

### Solution

Correct option is

4.9 mA, 0.1 mA

By definition, the a-c current-gain in common-base arrangement of a transistor is give by   = 4.9 mA

We know that the base-current is emitter-current minus collector-current, that is   = 0.1 mA.

#### SIMILAR QUESTIONS

Q1

The value of from factor of full wave rectifier is

Q2

When the p-end of the p-n junction is connected to the negative terminal of the battery and the n-end to the positive terminal of the battery, then thep-n junction behaves like :

Q3

n-type semiconductor is formed :

Q4

An n-type and a p-type silicon can be obtained by doping pure silicon with :

Q5

An n-type semiconductor is :

Q6

The drift current in a p-n junction is :

Q7

The diffusion current in a p-n junction is

Q8

In a p-n-p transistor with normal bias:

Q9

The base-current of a transistor is and the collector-current is 2.05 mA. A change of in the base-current produces a change of 0.65 mA in the collector current. Find .

Q10

In a common-base amplifier the load-resistance of the output circuit is and the resistance of the input circuit is . If current-gain be 0.95, calculate the voltage-gain and the power gain.