Question

Solution

Correct option is

15 mA, 15.1 mA

By definition, the alternating-current gain is given by    = 15 mA

The emitter-current is   = 0.1 mA + 15 mA

= 15.1 mA.

SIMILAR QUESTIONS

Q1

An n-type and a p-type silicon can be obtained by doping pure silicon with :

Q2

An n-type semiconductor is :

Q3

The drift current in a p-n junction is :

Q4

The diffusion current in a p-n junction is

Q5

In a p-n-p transistor with normal bias:

Q6

The base-current of a transistor is and the collector-current is 2.05 mA. A change of in the base-current produces a change of 0.65 mA in the collector current. Find .

Q7

The current-gain of a transistor in a common-base arrangement is 0.98. Find the change in collector-current corresponding to a change of 5.0 mA in emitter-current. What would be the change in the base-current?

Q8

In a common-base amplifier the load-resistance of the output circuit is and the resistance of the input circuit is . If current-gain be 0.95, calculate the voltage-gain and the power gain.

Q9

In input and output resistances in a common-base amplifier circuit are respectively. If the current-gain is 0.98, then find the voltage gain. If the emitter-current is 2 mA, then find the collector-current and the base-current.

Q10

Find the voltage gain and power gain in a transistor amplifier in common-emitter configuration when and the input and the output ersistance are .