## Question

### Solution

Correct option is

1 gram-atom of  has a mass of 11 gram, and contains  atoms (the Avogadro’s number). Therefore, the number of atoms present (initially) in 2.2 mg

.

#### SIMILAR QUESTIONS

Q1

How much of 5.00 gram of polonium will decay in one year? The half-life of polonium is 138 days.

Q2

The half-life of a radioactive substance is  against . Calculate the decay rate for  atoms of the substance.

Q3

The half-life of  against . Calculate the activity of 1 g sample of . Avogadro’s number is .

Q4

The half-life of  is 28 years. How much is the disintegration rate of 15 mg of this isotope? The Avogadro’s number is .

Q5

1 g of particles per second. Find its half-life and average life. Avogadro’s number is .

Q6

Determine the amount of  required to provide a source of -particles of 5 millicurie strength. The half-life of Po is 138 days. The Avogadro’s number is

Q7

The disintegration rate of a certain radioactive sample at any instant is 4750 disintegrations per minute. 5 minute after, the rate becomes 2700 disintegrations per minute. Calculate the half-life of the sample. .

Q8

At a given instant are 25% undecayed radioactive nuclei in a sample. After 10 seconds, the number of undecayed nuclei reduces to 12.5%. Calculate the time in which the number of undecayed nuclei will further reduce to 6.25% of the reduced number.

Q9

The normal activity of a living mater containing radioactive carbon C14 is found to be 15 decays per minute per gram of carbon. An archaeological specimen shows an activity of 9 decays per minute per gram of carbon. Estimate the age of the specimen. The half-life of C14 is 5730 years.

Q10

A small quantity of solution containing  radionuclide (half-life 15 hours) of activity 1.0 microcurie is injected into the blood of a person. A sample of the blood of volume 1 cm3 taken after 5 hours show an activity of 296 disintegrations per minute. Determine the total volume of blood in the body of the person.

.