The Total Energy Of The Electron In The First Excited State Of Hydrogen Is –3.4 eV. What Is The Kinetic Energy Of The Electron In This State?  

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Question

The total energy of the electron in the first excited state of hydrogen is –3.4 eV. What is the kinetic energy of the electron in this state?  

Solution

Correct option is

+3.4 eV

The kinetic and potential energies of an electron in the nth excited state are given by  

            

  

adding (i) and (ii) we get the total energy E which is

           

               

Notice from (i) and (iii) that E = –KE. Given E = –3.4 eV.

Hence    KE = –E = –(–3.4) = +3.4 eV. 

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