Question

The ionisation potential of the hydrogen atom is 13.6 eV. Its energy in n = 2 energy state is

Solution

Correct option is

–3.4 eV

Ionization potential = energy of the electron in the first orbit of the atom = 13.6 eV.   

Its value in the second orbit is

        .

SIMILAR QUESTIONS

Q1

A proton and an electron move with the same velocity. The associated wavelength for proton is

Q2

Two particles of masses m and 2m have equal kinetic energies. Their de Broglie wavelength are in the ratio of 

Q3

The wavelength of de Broglie wave associated with a thermal neutron of mass m at absolute temperature T is given by (here k is the Boltzmann constant) 

Q4

The momentum of a photon of frequency v is

Q5

Which energy state of the triply ionized beryllium (Be+++) has the same electrons orbital radius as that of the ground state of hydrogen? Given Zfor beryllium = 4.

Q6

Which energy state of doubly ionized lithium (Li++) has the same energy as that of the ground state of hydrogen? Given Z for lithium = 3.

Q7

The total energy of the electron in the first excited state of hydrogen is –3.4 eV. What is the kinetic energy of the electron in this state?  

Q8

The energy of the electron of hydrogen orbiting in the stationary orbit of radius rn is proportional to

Q9

The energy required to excite a hydrogen atom from n = 1 to n = 2 energy state 10.2 eV. What is the wavelength of the radiation emitter by the atom when it goes back to its ground state?

Q10

The innermost orbit of the hydrogen atom has diameter of 1.06 Å. What is the diameter of the tenth orbit?