## Question

### Solution

Correct option is

None of these

Given circle

x2 + y2 = 2x = 0

centre of given circle is (1, 0)

Since normal is parallel to

x + 2y = 3

Let the equation of normal is

+ 2y = λ

Since normal passes through the centre of the circle i.e. (1, 0)

Then             1 + 0 = λ

∴                          λ = 1

The equation of normal is

x + 2y = 1

or                 x + 2y – 1 = 0

#### SIMILAR QUESTIONS

Q1

Find the equation of the circle which passes through the origin and makes intercepts of length a and b on axis of x and y respectively.

Q2

A circle of radius 2 lies in the first quadrant and touches both the axes of coordinate. Find the equation of circle with centre at (6, 5) and touching the above circle externally.

Q3

A circle of radius 5 units touches the coordinates axes in 1st quadrant. If the circle makes one complete roll on x axis along positive direction of xaxis. Find the equation in new position.

Q4

Discus the position of the points (1, 2) and (6, 0) with respect to the circle.

x2 + y2 – 4x + 2y – 11 = 0

Q5

Find the shortest and largest distance from the point (2, –7) to the circle

x2 + y2 – 14x – 10y – 151 = 0

Q6

Find the length of intercept on the S.L. 4x – 3y – 10 = 0 by the circle x2y2 – 2x + 4y – 20 = 0.

Q7

Find the coordinates of the middle point of the chord which the circle x2y2 + 4x – 2y – 3 = 0 cut off the line x – y + 2 = 0.

Q8

For what values of λ will the line y = 2x + λ be a tangent to the circle x2y2 = 5.

Q9

Find the equation of tangent to the circle x2 + y2 – 2ax = 0 at the point Q10

Find the equation of normal at the point (5, 6) to the circle;

x2 + y2 – 5x + 2y – 48 = 0