Find the equation of normal to the x2 + y2 = 2x which is parallel to x + 2y= 3.
None of these
x2 + y2 = 2x = 0
centre of given circle is (1, 0)
Since normal is parallel to
x + 2y = 3
Let the equation of normal is
x + 2y = λ
Since normal passes through the centre of the circle i.e. (1, 0)
Then 1 + 0 = λ
∴ λ = 1
The equation of normal is
x + 2y = 1
or x + 2y – 1 = 0
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