Question

Find the equation of that chord of the x2 + y2 = 15 which is bisected at (3, 2).

Solution

Correct option is

 

  

            

SIMILAR QUESTIONS

Q1

Find the equation of the tangent to the circle x2 + y2 = 16 drawn from the point (1, 4).

Q2

Find the equation of the image of the circle x2 + y2 + 16x – 24y + 183 = 0 by the line mirror 4x + 7y + 13 = 0.

Q3

Find the equation of the normal to the circle x2 + y2 = 2x, which is parallel to the line x + 2y = 3.

Q4

 

Find the equation of the circle which cuts orthogonally each of the three circles given below: 

x2 + y2 – 2x + 3y – 7 = 0, x2 + y2 + 5x – 5y + 9 = 0 and x2 + y2 + 7x – 9x + 29 = 0.

Q5

Circum centre of the triangle PT1T2 is at

Q6

If P is taken to be at (h, 0) such that P’ lies on the circle, the area of the rhombus is

Q7

Locus of mid-point of the chords of contact of x2 + y2 = 2 from the points on the line 3x + 4y = 10 is a circle with centre P. If O be the origin then OP is equal to

Q8

Suppose ax + bx + c = 0, where abc are in A.P. be normal to a family or circles. The equation of the circle of the family which intersects the circle x2 + y2 – 4x – 4y – 1 = 0 orthogonally is

Q9

Find the equation of chord of x2 + y2 – 6x + 10y – 9 = 0 which is bisected at (–2, 4).

Q10

 

Find the centre and radius of the circle 

             2x2 + 2y2 = 3x – 5y + 7