Question

Solution

Correct option is

SIMILAR QUESTIONS

Q2

The maximum value of  under the restrictions 

Q3

 the value of 

Q4

 

 

Q8

If tan α is equal to the integral solution of the inequality 4x2 – 16x + 15 < 0 and cos β is equal to the slope of the bisector of the first quadrant, then sin (α + β) sin (α – β) is equal to  

Q9

0, then the value of tan x tan y  tan z  tan t is equal to

 

Q10

If A and B are acute positive angles which satisfy the equalities  then

A + 2B is equal to