If displacement of a particle is zero, the distance covered
The numerical value of the ratio of average velocity to average speed is
The moving body is covering the displacement directly proportional to the square of the time. The acceleration of the body is
If two balls of same density but different masses are dropped from a height of 100 m, then (neglect air resistance)
The position x of a particle varies with time (t) as x = at2 – bt. The acceleration at time t of the particle will be equal to zero, where t is equal to
A body covers one-third of the distance with a velocity v1, the second one-third of the distance with a velocity v2 and the remaining distance with a velocity v3. The average velocity is
Between the two station, a train accelerates from res uniformly at first, then moves with constant velocity and finally retards uniforms to come to rest. If the ratio of the time taken be 1 : 8 : 1 and the maximum speed attained be 60 km/h, then what is the average speed over the whole journey ?
A particle moving in a straight line covers half the distance with speed of 3 m/s. The other half of the distance is covered in two equal time intervals with speeds of 4.5 m/s and 7.5 m/s, respectively. The average speed of the particle during this motion is
Taxies leave the station X for Y every 10 min. Simultaneously, a taxi also leaves the station Y for station X every 10 min. The taxies move at the same constant speed and go from X and Y or vice-versa in 2h. How many taxies coming from the other side will meet each taxi enroute from Y and X?
The relation between time t and distance x is where are constant. The retardation is