## Question

A body oscillates harmonically with amplitude 0.05 m. At a certain instant of time its displacement is 0.01 m and acceleration is 1.0 ms^{-2}. What is the period of oscillation?

### Solution

Displacement *x* = + 0.01 m. therefore, acceleration *a* = –1.0 ms^{–2}.

Now

Which gives, ω = 10 rad s^{–1}. Therefore,

#### SIMILAR QUESTIONS

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