## Question

### Solution

Correct option is

0.5 s

Let A and B be the two extreme positions of the particle with O as the mean position. Displacements to the right of O are taken as positive while those to the left of O are taken as negative

Let the displacement of the particle is SHM be given by

..(i)

let us suppose that at time t = 0, the particle is at extreme position B. Setting x = A and t = 0 in Eq. (i) we have

A = A sin Ï•

Giving

Where        A = 25 cm.

Now let us say that the particle reaches point C at t = t1 and point D at t =t2. At C, the displacement x(t1) = + 12.5 cm and at D, it is x(t2) = –12.5 cm (see fig.) so from (ii) we have

Notice that cos ωt2 = –0.5 even for  This value of t2 does not correspond to the minimum time because this is the time at which the particle, moving to left, reaches A and then returns to D.

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