﻿ A spring with no mass attached to it hangs from a rigid support. A mass mis now hung on the lower end to the spring. The mass is supported on a platform so that the spring remains relaxed. The supporting platform is then suddenly removed and the mass begins to oscillate. The lowest position of the mass during the oscillation is 5 cm below the place where it was resting on the platform. What is the angular frequency of oscillation? Take g = 10 ms–2. : Kaysons Education

# A Spring With No Mass Attached To It Hangs From A Rigid Support. A Mass mis Now Hung On The Lower End To The Spring. The Mass Is Supported On A Platform So That The Spring Remains Relaxed. The Supporting Platform Is Then Suddenly Removed And The Mass Begins To Oscillate. The Lowest Position Of The Mass During The Oscillation Is 5 Cm Below The Place Where It Was Resting On The Platform. What Is The Angular Frequency Of Oscillation? Take G = 10 Ms–2.

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## Question

### Solution

Correct option is

It is clear from fig that the separation between the two extreme position of the oscillating mass is 5 cm. Therefore, the equilibrium position O is 2.5 cm below the supporting platform. In other words, force m g produces an extension

y = 2.5 cm in the spring. If k is the force

constant of the spring we have

The angular frequency ω of oscillation is

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