Question

The number of integral values of k for which the equation 7 cos x + 5 sin x = 2k + 1 has a solution is

 

Solution

Correct option is

8

The given equation can be written as r cos (x - α) = 2k + 1 where r

cos α = 7, r sin α = 5

      

      

           

      

      

      

Which gives 8 integral values of k.

SIMILAR QUESTIONS

Q1

  

      

Q2

If 0 < A < π/2 the value of the expression

   

Q3

The value of the expression 

Q4

Let f (θ) = sin θ (sin θ + sin 3θ), then f (θ)

Q6

If αβ are positive acute angles and  then tan α = k tanβ such that

Q7
Q9

The maximum value of (cos α1) (cos α2) …(cos αn) under the restriction 0 ≤ α1, α1,…., α1 ≤ π/2 and (cos α1) (cos α2) …

(cos αn) = 1 is

Q10