Question

 then the value of tan α tan 2α tan 3α….tan(2n-1)α is equal to

Solution

Correct option is

1

tan α tan 2α tan 3α….tan(2n-1)α

      = {tan α  tan(2n – 1) α} {tan 2α tan (2n – 2)α}…{tan(n-1)α           tan(n+1)α} tan nα,

      ={tan α tan(π/2- α)} {tan 2α tan(π/2- 2α)}….tan π/4 = 1.1.1…1=1

SIMILAR QUESTIONS

Q1

If sec A tan B + tan A sec B = 91, then the value of (sec A sec B + tan A tan B)2 is equal to

Q2

The values of θ lying between 0 and π/2 and satisfying the equation

                      

Q3

Find the maximum and minimum values of 6 sin x cos x + 4 cos 2x.

Q4

 

Q5
Q8
Q9

Which of the following statement is correct

Q10

The number of solution of the equation

  is/are