The set is equal to
If log1/5 x ≤ 1 i.e. x ≥ 1/5 then the give equality reduces to
1 – log1/5 x + 2 = 3 – log1/5 x which is trivially true. If 1 < log1/5 x ≤ 3 then the given equality becomes log1/5 x – 1 + 2 = 3 – log1/5 x
⇒ 2log1/5 x = 2⇒ log1/5 x = 1 which is not true.
Also if log1/5 x – 3 than the given equality reduces to log1/5 x – 1 + 2 = log1/5 x – 3 which clearly is not true.
Hence the required set is equal to [1/5, ∞].
The set of all x satisfying the equation
The set of all solutions of the inequality contains the sets
The set of all the solutions of the inequality
If log3 x + log3 y = 2 + log3 2 and log3 (x + y) = 2 then
The set of all solutions of the equation
then the value of log30 8
then the value of ab + 5(a – b) is
The set of all values of x satisfying
The set of is equal to