Question

Solution

Correct option is As the point mass m is outside the lead sphere we can assume its mass to be concentrated at the centre. To calculate the force of attraction on the point mass m we should calculate the force due to the solid sphere and subtract from this the force which the mass of the hollowed sphere would have exerted on m, i.e.,   SIMILAR QUESTIONS

Q1

A space-craft is launched in a circular orbit near the earth. How much more velocity will be given to the space-craft so that it will go beyond the attraction force of the earth. (Radius of the earth = 6400 km, g = 9.8 m/s2).

Q2

An artificial satellite of mass 200 kg revolves around the earth in an orbit of average radius 6670 km. Calculate its orbital kinetic energy, the gravitational potential energy and the total energy in the orbital.

(Mass of earth = 6.0 × 1024 kg, G = 6.67 × 10–11 Nm2 kg –2).

Q3

With what velocity must a body be thrown upward from the surface of the earth so that it reaches a height of 10 Re? Earth’s mass and G = 6.67 × 10 –11 Nm2kg–2.

Q4

A rocket is launched vertically from the surface of the earth with an initial velocity of 10 km s–1. How far above the surface of the earth would it go? Mass of the earth = 6.0 × 1024 kg, radius = 6400 km and G = 6.67 × 10 –11 Nm2 kg –2

Q5

The escape velocity of a body from earth is 11.2 km s–1. If the radius of a planet be half the radius of the earth and its mass be one-fourth that of earth, then what will be the escape velocity from the planet?

Q6

A body is at a height equal to the radius of the earth from the surface of the earth. With what velocity be it thrown so that it goes out of the gravitational field of the earth? Given: N m2 kg–2.

Q7

A particle falls on the surface of the earth from infinity. If the initial velocity of the particle is zero and friction due to air is negligible, find the velocity of the particle when it reaches the surface of the earth. Also find its kinetic energy. (Radius of earth is 6400 km and g is 9.8 m/s2.)

Q8

A mass of is to be compressed in the form of a sphere. The escape velocity from its surface is What should be the radius of the sphere. Gravitational constant Q9

Imagine a planet whose diameter and mass are both one-half of those of earth. The day’s surface temperature of this planet reaches upto 800 K. Are oxygen molecules possible in the atmosphere of this planet? Give calculation. (Escape velocity on earth’s surface = 11.2 km s–1, Boltzmann’s constant

k = 1.38 × 10–23 JK–1, mass of oxygen molecule = 5.3 × 10–26 kg.)

Q10

What are the values of gravitational attraction and potential at the surface of earth referred to zero potential at infinite distance? Given that the mass of the earth is the radius of earth is 6400 km and G = 6.67 ×10 –11MKS units.