It is possible to project a particle with a given velocity in two possible ways so as to make it pass through a point P at a distant r from the point of projection. The product of the times taken to reach this point in the two possible ways is then proportional to
The range of a projectile is the two possible angles of projection are θ and . The time of flight corresponding to these two angles are
Thus t1t2 ∝ r.
At what angle (θ) with the horizontal should a body be projected so that its horizontal range equals the maximum height it attains?
A body is projected horizontally from a point above the ground. The motion of the body is described by the equations
x = 2t
and y = 5 t2
Where x and y are the horizontal and vertical displacements (in m) respectively at time t. The trajectory of the body is
A body is projected at time t = 0 from a certain point on a planet’s surface with a certain velocity at a certain angle with the planet’s surface (assumed horizontal). The horizontal and vertical displacement x and y (in metres) respectively vary with time t
(in seconds) as
What is the magnitude and direction of the velocity with which the body is projected?