﻿ A particle moves along a straight line such that its displacement at any timet is given by s = (t3 + 6t2 + 3t + 4)m. What is the velocity of the particle when its acceleration is zero? : Kaysons Education

# A Particle Moves Along A Straight Line Such That Its Displacement At Any Timet is Given By S = (t3 + 6t2 + 3t + 4)m. What Is The Velocity Of The Particle When Its Acceleration Is Zero?

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## Question

### Solution

Correct option is

– 9 m/s

As according to given problem,

S = t3 – 6t+ 3+ 4

Instantaneous velocity

v = ds/dt = 3t2 – 12+ 3                        …(1)

and acceleration

So acceleration will be zero when 6t – 12 = 0, i.e., t = 2 sec. And the so velocity when acceleration is zero, i.e., at  = 2 sec from Eqn. (1), will be

v = 3 × 22 – 12 × 2 + 3 = – 9 m/s.

#### SIMILAR QUESTIONS

Q1

If the initial velocity of the particle is u and collinear acceleration at any time t is at, calculate the velocity of the particle after time t.

Q2

A particle starts moving from the position of rest under a constant acc. If it travels a distance x in t sec, what distance will it travel in next t sec?

Q3

A particle moving with velocity equal to 0.4 m/s is subjected to an acceleration of  0.15 m/s2 for 2 sec in a direction at right angle to its direction of motion. What is the magnitude of resultant velocity?

Q4

Two particles A and B move with constant velocities v1 and v2 along two mutually perpendicular straight lines towards the intersection point O. At moment t = 0 the particle were located at distances l1 and l2 from O respectively. Find the time when they are nearest and also this shortest distance.