A particle starts moving from the position of rest under a constant acc. If it travels a distance x in t sec, what distance will it travel in next t sec?


Correct option is

= 3x


As acc. Is constt., from 2nd equation of motion,



Now if it travels a distance y in next t sec., the total distance travelled in (tt = 2t) sec will be x + y; so


Dividing Eqn. (2) by (1),


Alternative Solution:-

From 2nd equation of motion, we have


The velocity of particle after time t from 1st equation of motion will be

           v = 0 + at,     i.e.,    v = at

Now for next t sec it will be the initial velocity; so again from 2nd equ. of motion,


Dividing equ. (4) by (3),

                             (y/x) = 3,  i.e.,      y = 3x.



If the initial velocity of the particle is u and collinear acceleration at any time t is at, calculate the velocity of the particle after time t.


A particle moves along a straight line such that its displacement at any timet is given by s = (t3 + 6t2 + 3t + 4)m. What is the velocity of the particle when its acceleration is zero?


A particle moving with velocity equal to 0.4 m/s is subjected to an acceleration of  0.15 m/s2 for 2 sec in a direction at right angle to its direction of motion. What is the magnitude of resultant velocity?


Two particles A and B move with constant velocities v1 and v2 along two mutually perpendicular straight lines towards the intersection point O. At moment t = 0 the particle were located at distances l1 and l2 from O respectively. Find the time when they are nearest and also this shortest distance.



A body starting from rest slides on an inclined plane of length s as shown in Fig. Calculate the time of descent and speed at the bottom. Find also

(a)  Distance covered in half the time of descent and (b) time taken to cover half the distance