A Juggler Throws Balls Into Air. He Throws One Whenever The Previous One Is At Its Highest Point. How High Do The Balls Rise If The Throws N Balls Each Sec? Acceleration Due To Gravity Is G.

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Question

A juggler throws balls into air. He throws one whenever the previous one is at its highest point. How high do the balls rise if the throws n balls each sec? Acceleration due to gravity is g.

None of these

easy

Solution

Correct option is

As the juggler is throwing n balls each second and 2^nd when the first is at its highest point, so the time taken by one ball to reach the highest point,

t = (1/n)s

and as at highest point v = 0, from 1^st equation of motion,

0 = u – (g)(1/n), i.e., u = (g/n) …(1)

Now from 3^rd equation of motion, i., v² = u² + 2as,

0 = u² – 2gh, i.e., h = (u²/2g)

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