## Question

### Solution

Correct option is

1512

We can choose two men out of 9 in 9C2 ways. Since no husband and wife are to play in the same game, to women out of the remaining 7 can be chosen in 7C2 ways. If M1M2W1 and W2 are chosen, then a team may consist of M1 and W1 or M1 and W2. Thus, the number of ways of arranging the game is #### SIMILAR QUESTIONS

Q1

Let P be a prime number such that P  23. Let n = p! + 1. The number of primes in the list n + 1, n + 2, n + 3, … n + p – 1 is

Q2

The term digit of 1! + 2! + 3! + … + 49! Is

Q3

Four dice are rolled. The number of possible outcomes in which least one die shows 2 is

Q4

A is a set containing n elements. A subset P of A is chosen. The set A is reconstructed by replacing the elements of P. A subset Q of A is again chosen. The number of ways of choosing P and Q so that P  Q = Ï• is

Q5

Let E = {1, 2, 3, 4} and F = {ab}. then the number of onto functions from E to F is

Q6

The number of ways of arranging letters of the word HAVANA so that V and N do not appear together is

Q7

The range of function Q8

The number of ways of arranging letters of the word RACHIT so that the vowels are in alphabetical order is

Q9

A five digit number divisible by 3 is to be formed using the numerals 0, 1, 2, 3, 4 and 5 without repetition. The total number of ways in which this can be done is

Q10

The number of times the digit 3 will be written when listing the integers from 1 to 1000 is