## Question

### Solution

Correct option is

156 Hz

The frequency of the wire when its vibrating length is L1 = 95 cm and when its vibrating length L2 = 100 cm are given by

Thus V1 > V2. If N is the frequency of the tuning then

Using (ii) in (i) we get V1 = 160 Hz and V2 = 152 Hz. Now V1 – N = 4 orN = V1 – 4 = 160 – 4 = 156 Hz.

#### SIMILAR QUESTIONS

Q1

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Q2

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Q10

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