Question
Sum of all three digit numbers (no digit being zero) having the property that all digit are perfect squares, is

3108

6216

13986

None of these
easy
Solution
13986
∴ Sum due to 1 at unit’s place is 1 × 9. Similarly.
Sum due to 1 at ten’s place is 1 × 10 × 9 and sum due to 1 at hundred’s place is 1 × 100 × 9. We can deal with the digit 4 and 9 in a similar way.
Thus, sum of the desired number is
.
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