A Particle Is Executing Simple Harmonic Motion Along The x-axis With Amplitude 4 Cm And Time Period 1.2 S. The Minimum Time Taken By The Particle To Move From x = +2 Cm To x = +4 Cm And Back Again Is

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A particle is executing simple harmonic motion along the x-axis with amplitude 4 cm and time period 1.2 s. The minimum time taken by the particle to move from x = +2 cm to x = +4 cm and back again is


Correct option is

0.4 s


Let the displacement of the particle be given by


Where      A = 4 cm and T = 1.2 s. If t1 is the time taken by the particle to move from x = 0 to x = 2 cm, then


Which gives       t1 = T/12. If t2 is the time taken to move from x = 0 to x= 4 cm, then


Which gives t2  Therefore, time taken to move from x = 2 cm to x = 4 cm is  Therefore, time taken by the particle to move from x = 2 cm to x = 4 cm and back = 0.4 s.



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