## Question

### Solution

Correct option is

A and B

In the position of minimum deviation, the refracted ray becomes parallel to the base of the prism. In the given problem, this condition is fulfilled by the prisms A and B

#### SIMILAR QUESTIONS

Q1

A ray of light passes through an equilateral prism of glass in such a manner that the angle of incidence is equal to the angle of emergence and each of these angles is equal to (3/4) of the angle of prism. The angle of deviation is:

Q2

If one face of a prism of prism angle 30o and is silvered, the incident ray retraces its initial path. The angle of incidence is:

Q3

Angle of a prism is A and its one surface is silvered. Light rays falling at an angle of incidence of 2A on first surface return back through the same path after suffering reflection at the second silvered surface. Refractive index of the material is:

Q4

An isosceles prism of prism angle 120o has a refractive index of 1.44. Two parallel monochromatic rays enter the prism parallel to each other in air as shown in figure. The rays emerging from the opposite faces: Q5

The angle of prism is 60o and its refractive index is 1.5. There will be no emergent light if the angle of incidence on the first face is:

Q6

A glass prism of refractive index 1.5 is immersed in water (refractive index 4/3). A light beam incident normally on the face AB is totally reflected to reach the face AC if: Q7

The angle of a prism is A and if the angle of minimum deviation is 180 – 2A, then the refractive index of the material of the prism is:

Q8

An equilateral prism is placed on the prism table of a spectrometer in the position of minimum deviation. If the angle of incidence is 60o, the angle of deviation of the rays is:

Q9

A ray falls on a prism ABC (AB = BC) and travels as shown in the figure. The minimum refractive index of the material should be: Q10

Angle of minimum deviation for a prism of refractive index 1.5 is equal to the angle of prism. The angel of the prism is:

(Given cos 41o ≈ 0.75)