## Question

### Solution

Correct option is

+ 2.67 D

The person is hypermetropic. This defect is correct by using a convex lens. Putting u = –30 cm and v = 1.5 m = –150 cm in the lens formula gives f = +37.5. Therefore, the lower of the lens = +2.67 D.

#### SIMILAR QUESTIONS

Q1

A ray of light in a medium of refractive index μ1 is partly reflected and refracted at the boundary of a medium of refractive index μ2, as shown in fig. If BOC = 90o. The value of angle i is given by Q2

A rectangular block of glass of refractive index μ and thickness d is placed over an ink dot made on a pice of paper lying on a table. When viewed from above, the dot will appear to be raised by an amount given by

Q3

Two transparent media A and B are separated by a plane boundary. The speed of light in medium A is and in medium B The critical angle for which a ray of light going from A toB is totally internally reflected is

Q4

A convex glass lens (μg = 1.5) has a focal length of 8 cm when placed in air. What is the focal length of the lens when it is immersed in water (μw = 4/3)?

Q5

A plano-concave lens is made of glass of refractive index 1.5 and the radius of curvature of the curved face is 50 cm. The power of the lens is

Q6

A convex lens of focal length 50 cm and a concave lens of focal length 100 cm are separated by a distance of 10 cm. What is the power of the combination?

Q7

How will the image formed by a convex lens be affected if the central portion of the lens is wrapped in black paper, as shown in fig. Q8

The equi-convex lens, shown in the figure, has a focal length f. What will be the focal length of each half if the lens it cut along AB? (See fig.) Q9

A person can see clearly only up to a distance of 30 cm. He wants to read a book placed at a distance of 50 cm from his eyes. What is the power of the lens he requires for his spectacles?

Q10

An object, a convex lens of focal length 20 cm and a plane mirror are arranged as shown in fig. How far behind the mirror is the final image formed? 