Question

A lens made of glass having refractive index 1.5 has a focal length of 50 cm in air. What will be its focal length if it is immersed in a liquid of refractive index 1.2?  

Solution

Correct option is

100 cm

 

The focal length of the lens is given by

                   

            

Now, refractive index of glass with respect to liquid  

= refractive index of air with respect to liquid × refractive index of glass with respect to air. That is

                 

Focal length of the glass lens immersed in liquid is given by

                                        …(ii)    

Dividing eq. (i) by (ii), we get

                    

                

SIMILAR QUESTIONS

Q1

A concave mirror forms a real image four times the size of the object placed at a distance of 10 cm from it. What is the radius of curvature of the mirror?   

Q2

In Young’s double slit experiment, the 10th maximum of wavelength λ1 is at a distance y1 from its central maximum and the 5th maximum of wavelength λ2 is at a distance y2 from its central maximum. The ratio y1/y2will be   

Q3

White light is used to illuminate the two slits in Young’s double slit experiment. The separation between the slits is d and the distance between the screen and the slit is D (>> d). At a point on the screen directly in front of on the slits, certain wavelengths are missing. The missing wavelengths are (here m = 0, 1, 2, … is an integer)     

Q4

In Young’s double slit experiment using two identical slits, the intensity of the maximum at the centre of the screen is I. What will be the intensity at the centre of the screen if one of the slits is closed?   

Q5

Glycerine (refractive index 1.4) is poured into a large jar of radius 0.2 m to a depth of 0.1 m. There is a small light source at the centre of the bottom of the jar. Find the area of the surface of glycerine through which the light passes.  

Q6

A ray of light travelling in glass (refractive index, ang = 3/2) is incident on a horizontal glass-air surface at the critical angle c. If a thin layer of water (refractive index, anw = 4/3) is now poured on the glass-air surface, at what angle will the ray of light emerge into air at the water-air surface?

Q7

The radius of curvature of the convex surface of a thin plano-convex lens is 20 cm. Refractive index of the medium of the lens is 1.5. Calculate the focal length of the lens.   

Q8

The thickness of a plano-convex lens is 4 cm. When it is placed on a horizontal table in such a way that its curved surface be in contact with the table, then the depth of a bottom-point of the lens appears 3 cm. If the lens is inverted so that its plane surface be in contact with the table, then the apparent depth of the centre of the lens-surface is found to be (25/8) cm. Determine the focal-length of the lens.     

Q9

The focal length of a convex lens in air is 20 cm. What will be its focal length if it is immersed in a liquid of refractive index 1.35? Refractive index of glass is 1.50.  

Q10

A convex lens of glass (refractive index 1.5) has both surfaces of radius of curvature 20 cm. Find its focal length and nature when it immersed in a liquid of refractive index 1.75.