﻿ The equation of a simple harmonic wave is y1 = 0.40 sin (314 t – 1.57 x) meter, and that of another similar wave is y2 = 0.20 sin (314t – 1.57x + 1.57) meter. Find the phase difference between these two waves and the ratio of their intensities.  : Kaysons Education

# The Equation Of A Simple Harmonic Wave Is y1 = 0.40 Sin (314 t – 1.57 x) Meter, And That Of Another Similar Wave Is y2 = 0.20 Sin (314t – 1.57x + 1.57) Meter. Find The Phase Difference Between These Two Waves And The Ratio Of Their Intensities.

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## Question

### Solution

Correct option is

Phase difference = 90o & ratio = 4

Comparing the two equations, we see that the phase difference between the waves is 1.57 radian. That is

The amplitude of the first wave is, a1 = 0.40 m; and that of the second wave is, a2 = 0.20 m. Therefore, the ratio of the amplitudes of the waves is

The intensity is proportional to the square of the amplitude.

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