## Question

The vertices of a triangle are *A*(10, 4), *B*(–4, 9) and *C*(–2, –1). Find the equation of the altitude through *A*.

### Solution

*x* – 5*y* + 10 = 0

Hence, equation of altitude *AD* which passes through (0, 4) and having slope 1/5 is

or *x* – 5*y* + 10 = 0

#### SIMILAR QUESTIONS

What are the inclination to the x-axis and intercept on y-axis of the line

?

Find the equation of the straight line cutting off an intercept of 3 units on negative direction of y-axis and inclined at an angle to the axis of *x*.

Find the equation to the straight line cutting off an intercept of 5 units on negative direction of y-axis and being equally inclined to the axes.

Find the equations of the bisectors of the angle between the coordinate axes.

Find the equation of a line which makes an angle of 135^{o} with positive direction of *x*-axis and passes through the point (3, 5).

Find the equation of the straight line bisecting the segment joining the points (5, 3) and (4, 4) and making an angle of 45^{o} with the positive direction of x-axis.

Find the equation of the right bisector of the line joining (1, 1) and (3, 5).

Find the equation to the straight line joining the points .

Let *ABC* be a triangle with *A*(–1, –5), *B*(0, 0) and *C*(2, 2) and let *D* be the middle point of *BC*. Find the equation of the perpendicular drawn from *B*to *AD*.

Find the equations of the medians of a triangle, the coordinates of whose vertices are (–1, 6), (–3, –9) and (5, –8).