﻿ A tangent to the ellipse  is cut by the tangent at the extremities of the major axis at T and T’. The circle on TT’ as diameter passes through the point : Kaysons Education

A Tangent To The Ellipse  is Cut By The Tangent At The Extremities Of The Major Axis At T and T’. The Circle On TT’ As Diameter Passes Through The Point

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Question

Solution

Correct option is

(0, 0)

Let  be a point on 4x2 + 9y2 = 36.

The equation of the tangent at P is

This meets the coordinate axes at

The equation of the circle with TT’ as diameter is

Clearly, it passes through (0, 0).

SIMILAR QUESTIONS

Q1

P is a variable point on the ellipse  with AA’ as the major axis. Then, the maximum value of the area of the triangleAPA’ is

Q2

The equation of the ellipse whose distance between the foci is equal to 8 and distance between the directrices is 18, is

Q3

The line x = at2 meets the ellipse  in the real points iff

Q4

On the ellipse 4x2 + 9y2 = 1, the points at which the tangents are parallel to the line 8x = 9y are

Q5

Tangent is drawn to the ellipse  , then the value of θ such that sum of intercepts on axes made by the tangent is minimum is

Q6

If p and p’ denote the lengths of the perpendicular from a focus and the centre of an ellipse with semi-major axis of length a, respectively, on a tangent to the ellipse and r denotes the focal distance of the point, then

Q7

If circumcentre of an equilateral triangle inscribed in  with vertices having eccentric angle α, β, γ respectively is (x1y1) then

Q8

Locus of the middle points of all chords of , which are at a distance of 2 units from the vertex of parabola y2 = –8axis

Q9

A point on the ellipse  at a distance equal to the mean of lengths of the semi-major and semi-minor axis from the centre, is

Q10

If C is the centre and A, B are two points on the conic

4x2 + 9y2 – 8x – 36y + 4 = 0 such that ∠ACB = π/2 then CA–2 +CB–2 is equal to