Question

If PSQ is a focal chord of the ellipse 16x2 + 25y2 = 400 such that SP = 8, then SQ =

Solution

Correct option is

2

 

We have, 

       

     

We know that the semi-latusrectum of an ellipse is the HM of the segments of a focal chord.

∴ HM of SP and SQ = Semi-latusrectum     

  

.

SIMILAR QUESTIONS

Q1

An ellipse has OB as a semi-minor axis, FF’ as its foci and the angle FBF’ is a right angle. Then, the eccentricity of the ellipse is

Q2

The focus of an ellipse is (–1, –1) and the corresponding directix is x – y + 3 = 0. If the eccentricity of the ellipse is 1/2, then the coordinates of the centre of the ellipse are 

Q3

 

The equation of the ellipse with its centre at (1, 2), one focus at (6, 2) and passing through (4, 6) is

Q4

Tangents are drawn to the ellipse  and the circle x2 + y2 = a2 at the points where a common ordinate cuts them (on the same side of the x-axis). Then, the greatest acute angle between these tangents is given by 

Q5

The area of the quadrilateral formed by the tangents at the end-points of latusrecta to the ellipse 

Q6

If α – β = constant, then the locus of the point of intersection of tangents at  to the ellipse   

Q7

Let S(3, 4) and S(9, 12) be two foci of an ellipse. If the coordinates of the foot of the perpendicular from focus S to a tangent to the ellipse is (1, –4), then the eccentricity of the ellipse is 

Q8

Let S and S’ be two foci of the ellipse . If a circle described on SS’ as diameter intersects the ellipse in real and distinct points, then the eccentricity e of the ellipse satisfies   

Q9

If PSQ is a focal chord of the ellipse , then the harmonic mean of SP and SQ is  

Q10

If S and S’ are two focii of the ellipse 16x2 + 25y2 = 400 andPSQ is a focal chord such that SP = 16, then SQ =