Question

Solution

Correct option is The equation of the ellipse is .

Let e be its eccentricity. Then, .

So, coordinates of its foci are (1, 0) and (–1, 0).

Let the equation of the hyperbola be It is given that and the hyperbola is confocal to the ellipse.    Hence the equation of the parabola is .

SIMILAR QUESTIONS

Q1

If the line y = 2x + λ be a tangent to the hyperbola 36x2 – 25y2 = 3600, then λ is equal to

Q2

From any point on the hyperbola tangents are drawn to the hyperbola . The area cut-off by the chord of contact on the asymptotes is equal to

Q3

PQ and RS are two perpendicular chords of the rectangular hyperbola xyc2. If C is the centre of the rectangular hyperbola, then the product of the slopes of CPCQCR and CS equal to

Q4

Let be two points on the hyperbola . If (hk) is the point of intersection of the normal of P and Q, then k is equal to

Q5

If x = 9 is the chord of contact of the hyperbola x2 – y2 = 9, then the equation of the corresponding pair of tangents is

Q6

If e and e’ be the eccentricities of two conics S = 0 and S’ = 0 and if e2 +e2 = 3, then both S and S’ can be

Q7

If e1 is the eccentricity of the ellipse and e2 is the eccentricity of the hyperbola passing through the foci of the ellipse and e1e2 = 1, then the equation of the parabola, is

Q8

The eccentricity of the conjugate hyperbola of the hyperbola x2 – 3y2 = 1 is

Q9

The slopes of the common tangents of the hyperbolas and Q10

The locus of point of intersection of tangents at the ends of normal chord of the hyperbola x2 – y2 = a2 is