﻿ The equation of the line passing through the centre of a rectangular hyperabola is x – y – 1 = 0. If one of its asymptotes is 3x – 4y – 6 = 0, the equation of the other asymptotes is : Kaysons Education

# The Equation Of The Line Passing Through The Centre Of A Rectangular Hyperabola Is x – y – 1 = 0. If One Of Its Asymptotes Is 3x – 4y – 6 = 0, The Equation Of The Other Asymptotes Is

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## Question

### Solution

Correct option is

4x + 3y + 17 = 0

The point of intersection of the line x – y – 1 = 0, which passes through the centre of the hyperbola, and the asymptotes 3x – 4y – 6 = 0 is the centre of the hyperbola. So, its coordinates are (–2, –3). Since asymptotes of a rectangular hyperbola are always at right angle. So, required asymptote is perpendicular to the given asymptote and passes through the centre (–2, –3) of the hyperbola and hence is equation is

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