## Question

Find the equation of the straight line cutting off an intercept of 3 units on negative direction of y-axis and inclined at an angle to the axis of *x*.

### Solution

3*x* – 5*y* – 15 = 0

Hence the equation of the line *y* = *mx* + *c*

or 3*x* – 5*y* – 15 = 0.

#### SIMILAR QUESTIONS

Find the angle between the lines joining the points (0, 0), (2, 3) and (2, –2), (3, 5).

The angle between two lines is and the slope of one of them is . Find the slope of the other line.

A line passes through the points *A*(2, –3) and *B*(6, 3). Find the slopes of the lines which are

1. parallel to *AB*

2. perpendicular to *AB*

Find the equation of the straight line parallel to y-axis and at a distance

(i).3 units to the right

(ii). 2 units to the left

Find the equation of the straight line parallel to *x*-axis and at a distance

(i). 5 units above the *x*-axis

(ii). 9 units below the *x*-axis

Find the equation of the straight line which passes through the point (2, –3) and is

1. parallel to the x-axis

2. perpendicular to the x-axis

Find the equation of a line which is equidistant from the lines .

If the straight line *y* = *mx* + *c* passes through the points (2, 4) and (–3, 6), find the values of *m* and *c*.

What are the inclination to the x-axis and intercept on y-axis of the line

?

Find the equation to the straight line cutting off an intercept of 5 units on negative direction of y-axis and being equally inclined to the axes.