Find The Equation Of The Straight Line Bisecting The Segment Joining The Points (5, 3) And (4, 4) And Making An Angle Of 45o with The Positive Direction Of X-axis.

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Question

Find the equation of the straight line bisecting the segment joining the points (5, 3) and (4, 4) and making an angle of 45o with the positive direction of x-axis.

Solution

Correct option is

x – y – 1 = 0

 

Here, m = slope of the line = tan 45o = 1. 

Let A be the mid-point of (5, 3) and (4, 4). Then the coordinates of A are 

             

Hence the required equation of the line is  

                    

or          x – y – 1 = 0

SIMILAR QUESTIONS

Q1

 

Find the equation of the straight line parallel to x-axis and at a distance

(i). 5 units above the x-axis

(ii). 9 units below the x-axis

Q2

 

Find the equation of the straight line which passes through the point (2, –3) and is  

1. parallel to the x-axis

2. perpendicular to the x-axis

Q3

Find the equation of a line which is equidistant from the lines .

Q4

If the straight line y = mx + c passes through the points (2, 4) and (–3, 6), find the values of m and c.

Q5

 

What are the inclination to the x-axis and intercept on y-axis of the line 

              ?

Q6

Find the equation of the straight line cutting off an intercept of 3 units on negative direction of y-axis and inclined at an angle  to the axis of x.

Q7

Find the equation to the straight line cutting off an intercept of 5 units on negative direction of y-axis and being equally inclined to the axes.  

Q8

 

Find the equations of the bisectors of the angle between the coordinate axes.

 

Q9

Find the equation of a line which makes an angle of 135o with positive direction of x-axis and passes through the point (3, 5).

Q10

Find the equation of the right bisector of the line joining (1, 1) and (3, 5).