﻿ Find the equation of the straight line passing through the point (2, 1) and through the point of intersecction of the lines x + 2y = 3 and 2x – 3y = 4. : Kaysons Education

# Find The Equation Of The Straight Line Passing Through The Point (2, 1) And Through The Point Of Intersecction Of The Lines x + 2y = 3 And 2x – 3y = 4.

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## Question

### Solution

Correct option is

5x + 3y – 13 = 0

Equation of any straight line passing through the intersection of the lines x+ 2y = 3 and 2x – 3y = 4 is

Since it passing through the point (2, 1)

Now substituting the value of λ in (i), we get

i.e.,  5x + 3y – 13 = 0

which is the equation of required line.

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