Question

Solution

Correct option is

21x + 77y – 101 = 0

Firstly make the constant terms (c1c2) positive    Hence “–” sign gives the obtuse bisector.

∴ Obtuse bisector is,  ⇒    21x + 77y – 101 = 0.

is the obtuse angle bisector.

SIMILAR QUESTIONS

Q1

If 3a + 2b + 6c = 0 the family of straight lines ax + by + c = 0 passes through a fixed point. Find the coordinates of fixed point.

Q2

Find the equation of the line passing through the point of intersection of the lines

x + 5y + 7 = 0, 3x + 2y – 5 = 0 and

1. parallel to the line 7x + 2y – 5 = 0

2. perpendicular to the line 7x + 2y – 5 = 0

Q3

Find the equation of straight line which passes through the intersection of the straight lines

3x – 4y + 1 = 0 and 5x + y – 1 = 0

and cuts off equal intercepts from the axes.

Q4

Find the orthocentre of the triangle of the triangle ABC whose angular points are A(1, 2), B(2, 3) and C(4, 3).

Q5

If the orthocentre of the triangle formed by the lines

2x + 3y – 1 = 0, x + 2y – 1 = 0, ax + by – 1 = 0   is at origin, then find (a,b).

Q6

Find the equations of the straight lines passing through the point (2, 3) and inclined at π/4 radians to the line 2x + 3y = 5.

Q7

Find the equations to the straight lines passing through the point (2, 3) and equally inclined to the lines 3x – 4y – 7 = 0 and

12x – 5y + 6 = 0

Q8

Find the equations of angular bisector bisecting the angle containing the origin and not containing the origin of the lines

4x + 3y – 6 = 0 and 5x + 12y + 9 = 0.

Q9

Find the bisector of acute angle between the lines x + y – 3 = 0 and 7x – y+ 5 = 0.