Question

Solution

Correct option is

(4, 6)

Let the fourth vertex be . Since ABCD is a parallelogram, the diagonals bisect to each other.

i.e., mid point of BD = mid point  of AC   on equating abscissaes and cordinates, we get  Hence the coordinates of the fourth vertex SIMILAR QUESTIONS

Q1

Transform the equation into cartesian form.

Q2

Transform the equation into polar form.

Q3

Find the distance between the points where a > 0.

Q4

An equilateral triangle has one vertex at the point (0, 0) and another at . Find the coordinates of the third vertyex.

Q5

Let the opposite angular points of a square be (3, 4) and (1, –1). Find the coordinates of the remaining angular points

Q6

Find the circumcentre of the triangle whose vertices are (–2, –3), (–1, 0) and (7, –6). Also find the radius of the circumcircle.

Q7

Find the coordinates of the point which divides the line segment joining the points (5, –2) and (9, 6) in the ratio 3 : 1.

Q8

Find the length of median through A of a triangle whose vertices are A(–1, 3), B(1, – 1)and C(5, 1).

Q9

Determine the ratio in which y – x + 2 = 0 divides the line joining (3, –1) and (8, 9).

Q10

The mid points of the sides of a triangle are (1, 2), (0, –1) and (2, –1). Find the coordinates of the vertices of a triangle with the help of two unknowns.