Question

The product of perpendiculars let fall from the point (x1y1) upon the lines represented by ax2 + 2hxy + by2, is

Solution

Correct option is

 

Let y – m1x = 0 and y – m2x = 0 be the lines represented by the equationax+ 2hxy + by2 = 0. Then,   

           

Let p1 and p2 be the lengths of perpendiculars from (x1y1) on lines y –m1x = 0 and y – m2x = 0. Then,   

      

  

  

   

  

SIMILAR QUESTIONS

Q1

The combined equation of the pair of lines through the origin and perpendicular to the pair of lines given by ax2 + 2hxy + by2 = 0, is   

Q2

Equation of The Pair of Straight Lines drawn through (1, 1) and perpendicular to the pair of lines 3x2 – 7xy + 2y2 = 0, is

Q3

The equation to the pair of lines perpendicular to the pair of lines 3x2 – 4xyy2 = 0, is

Q4

If the slope of one of the lines given by ax2 + 2hxy + by2 = 0 is 5 times the other, then

Q5

If the pair of lines ax2 + 2hxy + by2 = 0 and ax2 + 2hxy + by2 = 0 have one line in common, then (ab’ – ab)2 =

Q6

If one of the lines given by ax2 + 2hxy + by2 = 0 may be perpendicular to one of the lines given by ax2 + 2hxy + by2 = 0, then (aa’ – bb’)2 =

Q7

If the slope of one of the lines represented by ax2 + 2hxy + by2 = 0 be the square of the other, then   

Q8

The combined equation of the images of the pair of lines given by ax2 + 2hxy + by2 = 0 in the line mirror y = 0, is   

Q9

The difference of the tangents of the angles which the lines  make with X-axis, is 

Q10

 

The angle between the The Pair of Straight Lines