The equation represents three straight lines passing through the origin such that
They are equally inclined to one another
Let y = mx be one of the lines represented by the given equation. Then, y= mx satisfies it.
Hence the given equation represents three lines passing through the origin such that they are equally inclined with one another.
The orthocentre of the triangle formed by the pair of lines and the line x + y + 1 = 0 is
If the distance of a point (x1, y1) from each of the two straight lines, which pass through the origin of coordinates, is δ, then the two lines are given by
The equation of two straight lines through the point (x1, y1) and perpendicular to the lines given by
The equation of the straight lines through the point (x1, y1) and parallel to the lines given by
The triangle formed by the lines whose combined equation is
The combined equation of the pair of lines through the point (1, 0) and perpendicular to the lines represented by
The equation x3 + ax2y + bxy2 + y3 = 0 represents three straight lines, two of which are perpendicular, then the equation of the third line is
The combined equation of the lines L1 and L2 is 2x2 + 6xy + y2 = 0 and that of the lines L3 and L4 is 4x2 + 18xy + y2 = 0. If the angle between L1and L4 be α, then the angle between L2 and L3 will be
The lines represented by and the lines represented by are equally inclined then
If the equation represents two pairs of perpendicular lines, then